Find The Square Root Of 196 By Repeated Subtraction Method

Finding the square root of a number by repeatedly subtracting successive odd numbers from the given square number till you get zero is known as repeated subtraction method.

Find the square root of 196 by repeated subtraction method.

Sum of the first n odd natural numbers is equal to n 2. Square root by repeated subtraction. As explained in property 4 of square numbers and the square number is the sum of successive odd numbers starting from 1 and you can find square root of a number by repeatedly subtracting successive odd numbers which is also starting from 1 from the given square number till you get zero. In this article we will learn how to find the square root of a number through repeated subtraction.

First check whether the given number is a perfect square number or not. Find the square root of 169 by repeated subtraction method 4440731 1. Ex 6 3 3 find the square roots of 100 and 169 by the method of repeated subtraction. Answered find the square root of 169 by repeated subtraction method 2 see answers arshbbcommander arshbbcommander 169 1 168 168 3.

Based on the fact mentioned above repetitive subtraction of odd numbers starting from 1 until n becomes 0 needs to be performed. The count of odd numbers used in this process will give the square root of the number n. Mmmmcl1975 mmmmcl1975 29 06 2018 math secondary school 5 pts. Find square root of 16 by repeated subtraction method.

Finding square root using repeated subtraction method linkedin profile. 16 1 15 step 2. Therefore 4 is the square root of 16. 12 5 7 step 4.

Question from ncert maths class 8 chapter 6 exercise 6 3 question 3 squares and square roots cbse rbse up mp bihar board question text find the squ. 100 1 99 99 3 96 96 5 91 91 7 84 84 9 75 75 11 64 64 13 51 51 15 36 36 17 19 19 19 0 to find the square root we subtract successive odd numbers from the number till we obtain 0. Find the square root of the number 144 using repeated subtraction method. There are several methods for the same.

We know that the sum of the first n odd natural numbers is n 2. 15 3 12 step 3. 7 7 0 as you can see that given number 16 was repeatedly subtracted by successive odd numbers starting from 1 and we get zero in forth step.